Question
If 1/(x+ 1/(y+ 1/z)) = 13/30, then find x+y+z=
?Solution
Dividing numerator and denominator of RHS by 13. ⇒ (13/13)/(30/13) = 1/(30/13) = 1/(2+ 4/13) Again dividing by 4. ⇒ 1/(2+ (4/4)/(13/4)) = 1/(2+ 1/(13/4)) ⇒ 1/(2+ 1/(3+ 1/4)) ∴ x = 2, y = 3, z = 4 ∴ x+y+z= 9
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