Find ‘x’ if (x³+3x)/(3x²+1) = 189/61
Applying componendo and dividendo, (x³+3x+3x²+1)/(x³+3x-3x²-1) = (189+61)/(189-61)=250/128 ⇒ ((x+1)³)/((x-1)³) = 125/64 ⇒ (x+1)/(x-1) = 5/4 ⇒ x/1 = (5+4)/(5-4) ⇒ x = 9
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