ABCD is a cyclic quadrilateral in which AB =16.5 cm. BC = x cm. CD= 11 cm. AD 19.8 cm, and BD is bisected by AC at O. What is the value of x?
From the following figure, => ∠ACD = ∠ABD (angle made by a chord in same segment are equal) => ∠BDC = ∠BAC (angle made by a chord in same segment are equal) So, Δ AOB ~ Δ DOC by AA => OB/OC = 16.5/11 => OB = OD (given) => OD/OC = 16.5/11 ------ (i) As we know, => Δ ADO ~ Δ BCO => OD/OC = AD/BC => OD/OC = 19.8/x ------ (ii) Solving equation (i) and (ii) we get, => 19.8/x = 16.5/11 => x = (11 × 19.8)/16.5 => x = 13.2 cm
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
25.19% of (?2 ÷ 38.87 × 4679.94) = 6299.82 ÷ 419.78 × 50.15
36.22 of 249.98% + 299.99 ÷ 30.18 = ?
26.11 × 7.98 + 27.03 × 3.12 – 34.95 + 93.9 × 3.02 =?
What is the value of "π"
25.22% of (59.9 × 4.01) + 69.97 =?
80.22 of 149.98% + 459.99 ÷ 23.18 = ?
√323.89 × (3.20) ÷ 9.02 =?
21% of 6600 + 453.987 =?
? + 39.99 X 3.01 = √624.99 X 10.01% of 49.99