Question
If x ,y,z are three integers such that x +y = 8,y +z =13
and z +x =17,then the value of x2 /yz  is:Solution
x + y = 8 ----(1)  y + z = 13 ----(2) z + x = 17 ----(3) Eq (1) + (2) + (3), 2(x + y + z) = 8 + 13 + 17  x + y + z = 38/2 = 19 ----(4) From eq (3) and (4),  x + 13 = 19 x = 6 From eq(3), z + x = 17 z + 6 = 17 z = 11 From eq(2), y + z = 13  y + 11 = 13  y = 2 x2/yz = 62 / 2×11 =36 / 22=18/11
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