Question
Solution
15(β10 + β5) / β10 + β20 + β40 - β5 - β80 = ? = 15 (β10 + β5) / (β10 + 2β5 + 2β10 -β5 - 4β5) = 15 (β10 + β15) / 3β10 - 3β5 = 15(β10 + β5) / 3(β10 - β5) = 5(15 + 2β50) / 5 = 5(3 + 2β2)
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