If x + y = 2 and 1/x + 1/y = 18/15, then find the value of (x3 + y3)?
Given that, x + y = 2 and 1/x + 1/y = 18/15 Using, 1/x + 1/y = 18/15 (x + y)/xy = 18/15 2/xy = 18/15 Therefore, xy = 15/9 Now, by using formula x3 + y3 = (x + y) [(x + y)2 – 3xy] = 2 (4 – 3 × 15/9) = 2 (4 – 5) = -2
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