Fing the value of:
[(1024)(n/5) × (4)(2n+1) ] / [(16)n × (4)(n-1) ]
[(1024)(n/5) × (4)(2n+1) ] / [(16)n × (4)(n-1) ] ⇒ (〖(4⁵)〗(n/5) × 4(2n+1))/(42n × 〖4 〗(n-1) ) ⇒ (4^(n+2n+1) )/(4^(2n+n- 1) ) ⇒ (4(3n+1) )/(4(3n- 1) ) ⇒ 4(3n+1-3n+1) ⇒ 4² = 16
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