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    Question

    If a = 901, b= 903, and c= 906, then find the value of

    a³ + b³ +c³ –3abc?
    A 47960 Correct Answer Incorrect Answer
    B 56263 Correct Answer Incorrect Answer
    C 51490 Correct Answer Incorrect Answer
    D 51236 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    Given – a= 901, b=903, c = 906 Then as we know that  a³ + b³ +c³ –3abc = (a +b + c)/2 [(a-b) ² +(b-c) ² +(c-a) ²] = (901+903+906)/2 [4+9+25] =2710 / 2 [38] =2710×19= 51490

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