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For statement first – X =12, y=-2 and z= -10 x+ y+ z =12 -2-10=0 x +y + z=0 so. x³ + y³+ z³ = 3xyz = 3 ×12 × -2× -10 = 720 For statement second – x + y = 48, 4xy = 124 4x² +4y² = 4480 4(x² +y²) = 4480 4(x² +y²) = 4[ (x+ y) ²-2xy] =4[(48) ² -2×31] =4[2404-62] =4 ×2342=9368,
I. x2 - 9x - 52 = 0
II. y2 - 16y + 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 41x² - 191x + 150 = 0
Equation 2: 43y² - 191y +...
Between what values of x is the expression 19x - 2x2 - 35 positive?
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
If x² + 2x + 9 = (x – 2) (x – 3), then the resultant equation is:
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
I. x2 - 4x – 21 = 0
II. y2 + 12y + 20 = 0
l). 2p² + 12p + 18 = 0
ll). 3q² + 13q + 12 = 0
I. y/16 = 4/y
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)