Question
If a + b + c = 8, a² + b² + c² = 18 and ab + b c+ ca
= 12, then what is the value of a³ + b³ +c³ –3abc?Solution
Given – a + b + c = 8 a² + b² + c² = 18 ab + b c+ ca = 12 then a³ + b³ +c³ –3abc = (a+ b+ c) (a² + b² + c² -ab-b c-ca) = 8 (18-12) =8 ×6=48
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