Find the 36th term of the series 25, 29, 33……
The given series is in the Arithmetic progression. having First term (a) = 25 Common difference (d) = 29 – 25 = 33 – 29 = 4 So, the nth term (an) = a + (n – 1) × d So,36th term = 25 + (36 – 1) × 4 = 25 + 35 × 4 =25 + 140 = 165
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