If the first term of the arithmetic progression is 16, the common difference is 4, and the number of terms in the series are 40, then find the sum of the series.
First term (a) = 16 Common difference (d) = 4 Number of terms (n) = 40 Required sum = (n/2) {2a + (n – 1) × d} = (40/2) × {2 × 16 + (40 – 1) × 4} = 20 × (32 + 39 × 4) = 20× (32 + 156) = 20 × 188 = 3760
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