Question
If 10x2 β 6xy+yΒ² β 4x+4= 0, then find
the value of (3x+2y).Solution
10x2 β 6xy+yΒ² β 4x+4= 0 x2 -4x+4+9x2+y2-6xy=0 (x-2)2+(3x-y)2=0 When- x-2=0 x=2 3x-y =0 y=6 Now β 3x+2y =3Γ2+2x6=18.
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