What is the value of (a² + b²+4c²- ab-2bc-2ca) (a + b+2c):
(a + b + 2c) (a² + b² + 4c2- ab - 2bc - 2ca) As we know, = a3 + b³ + c3 – 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca) Put the value of c =2c. a³+b³ + 8c3 - 6abc = (a + b + 2c) (a² + b² + 4c2- ab - 2bc - 2ca). answer is a³+b³ + 8c3 - 6abc.
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