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    Question

    Find the values of x and y if 0.1x + 0.05y = 20 and

    0.3(x+2) +0.6y = 66.
    A 194 and 12 Correct Answer Incorrect Answer
    B 125 and 12 Correct Answer Incorrect Answer
    C 1.25 and 1.2 Correct Answer Incorrect Answer
    D 19.4 and 10 Correct Answer Incorrect Answer

    Solution

    0.1x + 0.05y = 20 10x+5y =2000 2x+y=400┬а┬а┬а┬а┬а┬а┬а┬а Y = 400-2xтАж (1) 0.3(x+2) +0.6y = 66. 3x+6+6y =660 3x+6y=654┬а┬а┬а put the value of Y 3x +6(400-2x) =654 3x +2400-12x =654 9x =1746 x =194. and putting the value of x in eq-1 we get, y = 400 - 2(194) = 400 - 388 = 12

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