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We'll simplify 5x² - 13xy + 6y2 = 0, by splitting the xy term 5x2 -10xy - 3xy + 6y2 = 0 = 5x (x-2y) - 3y (x-2y) = 0 = (5x-3y) (x – 2y) = 0 Taking, ⇒ 5x - 3y = 0 ⇒ 5x = 3y ⇒ x: y = 3:5 Taking, ⇒ x - 2y = 0 ⇒ x = 2y ⇒ x: y = 2:1 Finally x:y =3:5 or 2:1
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
(i) 2x² – x – 3 = 0
(ii) 2y² – 6y + 4 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
I. 7x² + 52x + 21 = 0
II. 6y² + 7y - 24 = 0
I. 2y2- 37y + 143 = 0
II. 2x2+ 15x – 143 = 0