If one of the roots of the equation x² – 18x + 72 = 0 is 6, then what is the other root?
x² – 18x + 72 = 0 x² – 12x-6x + 72 = 0 = x(x-12)-6(x-12) =0 =(x-6) (x-12) =0 When –(x-12) =0 x=12.
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