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      Question

      If 112 ├╖28 x 22 тАУ12 x 6 ├╖ 3 +12 = z, then

      find the value of z.
      A 6 Correct Answer Incorrect Answer
      B 2 Correct Answer Incorrect Answer
      C 8 Correct Answer Incorrect Answer
      D 4 Correct Answer Incorrect Answer

      Solution

      112 ├╖28 x 22 тАУ12 x 6 ├╖ 3 +12 = z 4 x 22 тАУ12 x 2 +12 = z 4 x 22 тАУ12 x 2 +12 = z 16-24+12=z Z=4.

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