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Given, {(4096) n/4 × 8 3n + 1 }/{(512) n × 8 n – 1 }
= {(8 4 ) n/4 × 8 3n + 1 }/{(8 3 ) n × 8 n – 1 }
= (8 4n + 1) /(8 4n – 1 ) (Since, a n × a m = a m + n )
= 8 4n + 1 – 4n + 1 (Since, a m /a n = a m – n )
= 8 2 = 64
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