If (x –4)3+(x–5)3+(x–6)3 = 3(x–4)(x–5)(x–6), Then x = ?
if a+b+c = 0 then a3+b3+c3 = 3abc and it is also vice versa. So Here (x –4)3+(x–5)3+(x–6)3 =0 so 3x-15 = 0 or x = 5 ` `
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