Get Started with ixamBee
Start learning 50% faster. Sign in now
ab + bc + ca = 0 bc = - ab – ca ca = - ab – bc ab = -bc –ca Now, 1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab) = 1/(a2 - (-ab - ca)) + 1/(b2 - (-ab - bc)) + 1/(c2 - (-bc-ca)) =1/(a2 + ab+ca) + 1/(b2 + ab+bc) + 1/(c2 + bc+ca) = 1/(a(a + b + c)) + 1/(b(a + b + c)) + 1/(c(a + b + c)) = (bc + ca + ab)/(abc(a + b + c)) = 0/(abc(a + b + c)) = 0
If x 2 – 15x + 51 = 0, then determine the value of (x – 5) + {1/(x – 5)}.
√(92×8 ×52+700) = ?
{(21/20) + (20/21)}2 - {(21/20) - (20/21)}2 = ?
In a college, the proportion of boys to girls is 7:9, and the proportion of graduate students to postgraduate students is 4:5. Determine the total numbe...
The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:
If a3 + b3 = 6240 and a + b = 30, then find the value of {(a + b)2 – 3ab}
If 15a2 + 1 = 20a, then find the value of {(9a2 + 1)/25a2}
1/3 + 1/15 + 1/35 + 1/63 + 1/99 = ?
In a class of 70 students and 25 teachers, each student got gifts that were 20% of total number of students and each teacher got gifts that were 10% of ...
