Question
If x² + y² + z² = xy + yz + zy (x≠0),
then the value of (5x+3y-4z)/2x isSolution
x² + y² + z² = xy + yz + zx (x≠0) If x² + y² + z² - xy - yz - zx = 0 Then x = y = z (5x+3y-4z)/2x = (5x+3x-4x)/2x = 4x/2x = 2
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