Question
A sum of ₹ 62 was divided among 100 students. If each
boy got 70 paisa and each girl got 45 paisa. Find the number of boys?Solution
₹ 62 = 6200 paisa For 100 students = 6200/100 = 62 paisa
Number of boys = 17/25 × 100 = 68
The graphs of the equations 3x-20y-2=0 and 11x-5y +61=0 intersect at P(a,b). What is the value of (a² + b² − ab)/(a² − b²...
√(92×8 ×52+700) = ?
1/3 + 1/15 + 1/35 + 1/63 + 1/99 = ?
189500 – 22650 + 48× ? – 352×18 = 162674
= ?If P3 + 3P2 + 3P = 7, then the value of P2+ 2P is –
...
If (x – 1/x) = 3, find (x³ – 1/x³).
If (x 2 = 10x – 25), then find the value of [x³ + (x⁴/25)][7 - x³]
If x + 1/x = 2, find x⁷ + 1/x⁷.