Question
In a 280-litre mixture (milk + water), the ratio of
quantities of milk and water is 3:4, respectively. How much water should be added to this mixture such that the ratio of the quantity of milk to that of water in the resultant mixture becomes 2:3?Solution
Initially, Quantity of milk in the mixture = {(3 Γ 280)/7} =120 liters Quantity of water in the mixture = {(4 Γ 280)/7} = 160 liters Let the quantity of water be added to the mixture = βxβ liters ATQ, {120/ (160 + x)} = 2/3 Or, 360 = 320 + 2x Or 2x = 40 x= 20 liters
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