A jug initially contains 80 liters of a mixture of milk and chocolate, with the quantity of chocolate being 30% of the total mixture. A liters of the mixture is taken out and replaced by chocolate, and the same quantity is repeated once more. If the final quantity of milk in the jug is 31.5 liters, what is the value of A?
ATQ, we can say that, Milk in 80 liters = 80 × 70/100 = 56 liters chocolate in 80 liters = 80 × 30/100 = 24 liters 31.5 = 56 × (1 – x/80)2 4.5/8 = (1 – x/80)2 4.5 × 80 × 80 / 8 = (80 – x)2 60 = 80 – x x = 20 liters
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