How many kilograms of wheat, priced at Rs 6.4/kg, should be mixed with 10 kg of gram flour priced at Rs 4.8/kg, such that by selling the mixture at a 20% profit, the selling price is Rs. 1.12 more than the average cost price per kg of both varieties of the mixture?
ATQ, we can say that Let the quantity of Rs 6.4/kg be a kg. S.P of mixture= Rs [1.12 + (6.4 + 4.8)/2]=1.12 + 5.6= Rs 6.72 According to question, =>(a × 6.4 + 4.8 × 10) × 120/100= 6.72(a + 10) =>6.4a × 120/100 + 48 × 120/100= 6.72a + 67.2 =>0.96a= 9.6 a= 9.6/0.96= 10kg.
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