Question
The difference between the present ages of a mother and
her son is 32 years. Six years ago, the mother was 4 years younger than twice the present age of her daughter. If the sum of the present ages of the son and the daughter is 34 years, find the present age of the father, who is 5 years older than the mother.Solution
ATQ, Let the present age of the daughter be 'z' years. Present age of the mother = '2z - 4' years Present age of the son = 'z - 32' years z + (z - 32) = 34 2z = 66 So, z = 33 years Therefore, present age of the father = Mother's age + 5 = (2z - 4) + 5 = (2 × 33) - 4 + 5 = 66 - 4 + 5 = 67 years.
Four of the five are alike in a certain way and hence forms a group. Who among the following does not belong to that group?
Six persons D, E, F, G, H and I sit around an equilateral triangular shaped table facing towards the centre. One person sits at each side of the table a...
How many persons sit between Priya and Sonam?
Six persons, F, G, H, I, J and K, sit in a row and face in north direction. Only two persons sit to the right of J. I sits immediate left of K. Neither ...
Who sits opposite to F?
Which of the following pairs represent those who sit at the extreme ends of the line?
Five friends, D, E, F, G and H, are sitting in a straight line. D and E are adjacent to each other. E is between D and F. D is third to the left of G. G...
How many persons sit between Y and the one who faces R?
Which of the following pairs represent the people sitting at extreme end of the rows?
Four of the following five are alike in a certain way and hence form the group. Which of the following ones does not belong to the group?
Relevant for Exams:
