A shopkeeper mixes two types of rice costing Rs 60 per kg and Rs 80 per kg in a ratio. He sells the mixture at Rs 85 per kg and gains a profit of 25%. If the total weight of the mixture is 80 kg, find the quantity of the cheaper rice used in the mixture (in kg).
Let the quantity of the cheaper rice (costing Rs 60 per kg) be x kg and the quantity of the costlier rice (costing Rs 80 per kg) be (80-x) kg. Total Cost price of the mixture = 60x + 80(80-x) = 6400 – 20x Total selling price of mixture = 80×85 = 6800 125% of cost price = 6800 Cost price = 6800/125 ×100 = 5440 6400 – 20x =5440 20x = 960 x = 48 quantity of the cheaper rice = x = 48 kg
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