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We know that, a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - bc - ab - ac) So, a3 + b3 + c3 - 3abc = 0 X (a2 + b2 + c2 - bc - ab - ac) [Since, a + b + c = 0]
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 25x² - 165x + 270 = 0
Equation 2: 27y² - 181y + ...
I. 10x2 + 33x + 9 = 0
II. 2y2 + 13y + 21 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
A sequence is provided below. Carefully analyze the given details and respond to the related query.
Sequence: 134, 70, 38,...
I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
One of the roots of the equation p2 - (y+3)p + 6y = 0 is cube of 2. What will be the difference of other root and 'y'.
I. x − √2401 = 0
II. y2 − 2401 = 0
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
