One type of liquid contains 15% of benzene, the other contains 20% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.
Let the percentage of benzene in the new mixture = x (20 - x)/(x - 15) = 6/4 = 3/2 5x = 85 x = 17 So, required percentage of benzene = 17%
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