Question
A person invests a sum of money
in a bank at a certain rate of interest. The interest earned at the end of the second and third years are Rs. 7,200 and Rs. 8,640, respectively. If the interest is compounded annually, find the interest earned at the end of the fourth year.Solution
ATQ,
In compound interest, the difference between interests earned in two consecutive years is the interest earned on the interest of the previous year. So, the difference between interest earned in the second and third years: = 8,640 - 7,200 = Rs. 1,440 So, rate of interest = (1,440/7,200) × 100 = 20% Therefore, interest earned in the fourth year = 8,640 × 1.2 = Rs.10,368
What will be the approximate value of the following questions.
(74.75% of 600.29 – 44.85% of 399.99) × (√224.95 ÷ 15.01) = ?
Which of the given trigonometric identities is incorrect ?
1. tan2 θ = sec2 θ - 1B. cosec2 θ = 1 + cot
22.11 × 4.98 + 23.03 × 5.12 – 32.95 + 96.9 × 5.02 =?
(424.98 ÷ 16.99 + ?) × 1.99 - 211.99 ÷ 2.01 = 24.98 × (4.012 - 3.99)Â
12.023 + 32.05 × 16.08 – 84.04% of 2400 = 56.06% of ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
12.99 × 9.99 + ? × 7 + 240.001 = 21.012Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
24.035 × √? = 4607.89 ÷ 11.8259Â
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