ATQ, Let the total task be 200 units {LCM (25 and 40)} So, efficiency of 'Ajay' = 200 ÷ 25 = 8 units/day And efficiency of 'Bijay' = 200 ÷ 40 = 5 units/day Task done in every 2 days = 8 + 5 = 13 units So, task done in 30 days by 'Ajay' and 'Bijay' = (30/2) × 13 = 195 units Time taken by 'Bijay' to do the remaining work = {(200 - 195)/5} = 1 day So, total time taken = 1 + 30 = 31 days
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