If the angular diameter of the sun is 20, how far from the eye a coin of radius 3.3 cm be kept to hide the sun?
Arc AB = Diameter of coin = 3.3× 2 = 6.6 cm θ = 20 = (20/60)θ = (1/3)θ θ in radian = ((1/3) x (22/7)/540)c= ((22/7)/540)c θ = arc/radius = (22/7)/540 = 6.6/r r = (6.6 x 540)/22× 7 = 1134 cm.
11, 1341, 3070, 5267, 8011, 11386
26, 38, 60, 110, 206, 398
21 32 54 86 131 186
...124, 128, 117, 135, 110, 146
12, 29, 64, 151, 322, 669
147 490 707 831 895 930
124, 186, 375, 930, 2790, 9765
224, 183, 144,115, 86, 63, 44.
76, 93, 112, 136, 156, 181
2, 6, 44, 462, 6930, 131670
