Question
In an A.P a9 = 40, then find sum of first 17 terms of
that A.P.Solution
General form of A.P is a, a + d, a + 2d, a + 3d….. Here a9 = 40; so 9th term is a + 8d = 40 then S17 =? ⇒ Sn = (n/2) [2 x a + (n – 1)d] = 0 ⇒ S17 = (17/2) [2a + 16d] ⇒ (17) [a + 8d] ⇒ 17 x 40 = 680
- The base of a right pyramid is an equilateral triangle with side 12 cm. If the height of the pyramid is 40√3 cm, calculate the volume of the pyramid.
In triangle ABC, the difference between angle A and angle B is 16°, and the difference between angle A and angle C is 8°. Determine the measure of an...
If area of similar triangles ∆ ABC and ∆ DEF be 64 sq Cm and 121 sq cm and EF = 15.4 cm then BC equals
Find the length of AB, if ΔABC ~ ΔRQP and AC = 22.5 cm, RP = 9 cm and RQ = 6 cm.
The angles of a triangle are in the ratio 4:5:3. Determine the sum of the smallest and largest angles of the triangle.
If the angles of a triangle are in the ratio of 2:5:8, then find the value of the biggest angle.
Find the area of a triangle whose sides are 12 m, 14 m, and 16 m.
In a right-angled triangle, the legs are in the ratio 3:4, and the hypotenuse is 25 cm. Find the perimeter of the triangle.
- A triangle has a base of 27.3 cm and the height is 11.4 cm. Find its area.
ABC is an equilateral triangle with sides of 24cm. Find the difference between its in-radius and circum-radius.
Relevant for Exams:
