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Here 1st term = a = 54 (which is the 1st term greater than 50 that is divisible by 6) The last term less than 200, which is divisible by 6 is 198 The number of terms in the in the AP; 54, 60, 66……..198 Here a = 54, d = 6 and number of terms = (198 – 54)/6 + 1 = 25 Sn = {n/2} [2a + (n – 1)d)] Sn = (25/2) [(2 x 54) + (24 x 6)] Sn = 3150
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