How many three digit numbers are divisible by 5?
nth = a + (n – 1)d Here, a → first term, n → Total number, d → common difference, n → n term Common difference, (d) = 5 Now, n = a + (n – 1)d ⇒ 995 = 100 + (n – 1) × 5 ⇒ 995 – 100 = (n – 1) × 5 ⇒ 895 = (n – 1) × 5 ⇒ 179 = (n – 1) ⇒ n = 180
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