Question
What will be the 11th term of the arithmetic progression
3, 8, 13, _____?Solution
Tn = a + (n - 1)d Where a = first term, n = number of terms and d = difference In the given series a = 3, d = 8 – 3 = 5 Tn = 3 + (11 – 1) 5 Tn = 3 + 50 Tn = 53 Eleventh term = 53
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