Question
Present average age of A, B and C together is 44 years.
Age of B is 12 Years hence from now will be 260% more than age of A, Four years ago from now while age of C after 12 years hence from now will be 50% more than the age of B 20 years ago from now. 4 years hence from now, what will be the ratio of ages of A and C? Desire difference.Solution
Let present age of A, B and C is a, b, and c respectively So a+b+c = 44*3= 132--------(1) And, (b+12) = 3.6*(a-4) 5b+60 = 18(a-4) 18a-5b=132---------(2) And, (c+12) = 1.5*(b-20) 3b-2c=84---------(3) Solving equation 1, 2 and 3 we get a=24, b = 60, and c = 48 Age of A, B 4 years hence now will be 28 and 52 respectively. Required ratio = 28:52 = 7:13
148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
3601 3602 1803 604 154 36
...8, 7, 12, 35, 128, 635
14, 28, 54, 98, 154, 224
104Â Â Â Â Â 136Â Â Â Â Â 152Â Â Â Â 160Â Â Â Â Â 164Â Â Â Â Â ?
...A’ is the nth term of the given series and ‘B’ is the (n + 1)th term of the given
series. Choose the correct statement from the following s...
7    7       14    42   ?     840
...11Â Â Â 12.1Â Â Â Â 14.3Â Â Â Â 17.6Â Â Â Â Â 22Â Â Â Â Â ?
9Â Â Â 4.5Â Â Â 4.5Â Â Â 9Â Â Â 36Â Â Â ?
40 30 20 ? 7.5 4.375
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