In a group of 3 numbers, the 1st is double of 2nd and half of third. If the average of the three numbers is 56 then find the difference between the third and first number.
Let 2nd number be x , 1st number be 2x & 3rd number be 4x, So (2x+x+4x)/3 = 24 or 7x/3 = 56 or x = 24 1st number = 2x = 48 3rd number = 4x = 96 Difference = 96 - 48=48.
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