In a group of 3 numbers, the 1st is double of 2nd and half of third. If the average of the three numbers is 56 then find the difference between the third and first number.
Let 2nd number be x , 1st number be 2x & 3rd number be 4x, So (2x+x+4x)/3 = 24 or 7x/3 = 56 or x = 24 1st number = 2x = 48 3rd number = 4x = 96 Difference = 96 - 48=48.
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In a group of three numbers first is double of second and half of third. The average of three numbers is 56. Find the difference between the first numb...
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In a division sum, the divisor is 12 times the quotient and also 5 times of the remainder. If the remainder is 48, then the dividend is:
