The average weight of 4 persons is 40 kg. The heaviest person’s weight is 26 kg more than the lightest person’s weight. If the average weight of the rest two persons is 40 kg, then find the weight of the heaviest person.
The sum of the weight of 4 persons = 40 × 4 = 160 kg Let the weight of the lightest person = ‘x’ kg The weight of the heaviest person = (x + 26) kg The sum of the weight of the remaining two persons = 40 × 2 = 80 kg According to the question, x + x + 26 + 80 = 160 2x = 54 x = 27 The weight of the heaviest person = 27 + 26 = 53 kg
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