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To maximize the toppers score, we must minimize the scores of everyone else. So, let the scores of other 7 students be 40 marks each. So, total marks obtained by 7 students = 40 X 7 = 280 Remaining marks = 680 - 280 = 400 So, score of toppers = 400 ÷ 3 = 133 marks + 1 additional mark This additional mark could be obtained by any other student.
If x = √7 + √6 and y = √7 - √6 , then the value of is (x2 + y2)/(x3 + y3).
...If (x + y + z) = 68, (x/z) = (3/4) and (z/y) = (2/5), then find the value of ‘y’.
(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?
If (x2 + y2 + z2 - 4x + 6y + 13) = 0, then find the value of (x + y + z).
(288 ÷ 8)² × (144 ÷ 24)³ = 24 × ? × (51840 ÷ 20)
If (a3+1)/(a+1) = (a3-1)/(a-1) and a ≠ 1, -1. Find the value of 'a'
What is the highest common factor of (x³ - x² - x - 15) and (x³ - 3x² - 3x + 9)?
If (a + b) = 7 and ab = 9, then find the value of (a2 + b2).
