The average of four numbers (z+16), (y+15), (y-25) and 1.2z is (y-6). If one more number which is 144 is added then the new average will be (y-1). The value of ‘z’ is what percentage of the value of ‘y’?
The average of four numbers (z+16), (y+15), (y-25) and 1.2z is (y-6).
(z+16)+(y+15)+(y-25)+1.2z = 4(y-6) Eq.(i)
If one more number which is 144 is added then the new average will be (y-1).
(z+16)+(y+15)+(y-25)+1.2z+144 = 5(y-1)
Put Eq.(i) in the above equation.
4(y-6)+144 = 5(y-1)
4y-24+144 = 5y-5
5y-4y = 144-24+5
y = 125
Put the value of ‘y’ in Eq.(i).
(z+16)+(125+15)+(125-25)+1.2z = 4(125-6)
(z+16)+140+100+1.2z = 4x119
(z+16)+140+100+1.2z = 476
256+2.2z = 476
2.2z = 476-256 = 220
z = 100
Required percentage = (100/125)x100
= (4/5)x100
= 80%
26 X √25 + 15 - 80% of 120 = ?2
(15 × 16) + 242= ? × 16
89 ÷ 512 × (1/64) = (23)?
120% of 25 + 80 X 2 = ?2 - 6
1404 ÷ 26 x 3 + 7 = ?2
(23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2
7, 8, 12, 21, 37, ?
500% of (121.8 + 16.4 – 28.2) = ? × 2
Determine the simplified value of the expression: 12 × 15 - 20 + 15 + 12 - 18 + 3 × 4 + 18.
22% of 280 + 34% of 1080 × 5/12 =? + 16% of 460