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The average of three numbers P, Q and R is 1600. P+Q+R = 1600x3 P+Q+R = 4800 Eq.(i) The ratio of P and Q is 4:5 respectively. Let’s assume P and Q are ‘4y‘ and ‘5y‘ respectively. R is 75% more than P. R = 175% of P R = 175% of 4y R = 1.75 x 4y R = 7y Put the values of ‘P’, ‘Q’ and ‘R’ in the Eq.(i). 4y+5y+7y = 4800 16y = 4800 y = 300 If R is 25% less than S. R = (100-25)% of S 7y = 75% of S 7y = 0.75xS Put the value of ‘y’ in the above equation. 7x300 = 0.75xS 2100 = 0.75xS 2100/0.75 = S S = 2800
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
I. 2y2 + 11y + 15 = 0
II. 3x2 + 4x - 4= 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
I. 5x² -14x + 8 = 0
II. 2y² + 17y + 36 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. 17x² - 26x – 16 = 0
II. 17y²- 26y + 9 = 0
I. 4x² - 15x + 9 = 0
II. 20y² - 23y + 6 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0