If average of first 9 numbers is (n – 50) and the sum of remaining number is 1620. Find the value of ‘n’, if the average of 21 numbers is ‘n’.
According to the question, => 21n = 9 × (n – 50) + 1620 => 21n - 9n = 1620 – 450 => n = 97.5
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