Question
If average of first 11 numbers is (n – 23) and the sum
of remaining number is 925. Find the value of ‘n’, if the average of 25 numbers is ‘n’.ÂSolution
According to the question, => 25n = 11 × (n – 23) + 925 => 25n - 11n = 925 – 253 => n = 48
More Average Questions
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y + ...
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 50x + 600 = 0
Equation 2: y² - 51y + 630 = 0
Relevant for Exams:
