A chef prepared 6 different dishes, and the average

Solution

ATQ, The total number of ratings to achieve in 20 dishes is 20 ratings with a goal of 30 each, which sums up to 600. For the first 6 dishes, the chef received a total rating of 6 dishes × 18 rating per dish = 108. In the subsequent 4 dishes, the chef's performance improved by 50%, resulting in a rating of 18 × 1.5 × 4 = 108. To meet the target of 600 total ratings for all 20 dishes,  the remaining 10 dishes should collectively earn 600 - (108 + 108) = 384. So, the required average rating for the remaining 10 dishes would be 384 divided by 10, which is 38.4.