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ATQ, Sum of the weight of 8 people = 75 × 8 = 600 kg Sum of the weights of all the people including the ones who joined later = 75 × 11 = 825 kg Total weight of three new people = 825 - 600 = 225 kg Let the weights of the three new people who joined the group be '3y', '4y', and '5y' kg, respectively. 3y + 4y + 5y = 225 Or, 'y' = (225/12) = 18.75 So, required difference between the heaviest and the lightest = 5y - 3y = 2y = 2 × 18.75 = 37.5 kg
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