Question

    Average of four consecutive prime numbers P1, P2, P3,

    and P4 is (13 + x). If the average of P1 and P2 is (10 + x) and the average of P3 and P4 is (10 + 2x), then find P4.
    A 25 Correct Answer Incorrect Answer
    B 65 Correct Answer Incorrect Answer
    C 45 Correct Answer Incorrect Answer
    D 23 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Sum of P1, P2, P3, and P4 = (13 + x) × 4 = 52 + 4x Sum of P1 and P2 = (10 + x) × 2 = 20 + 2x Sum of P3 and P4 = (10 + 2x) × 2 = 20 + 4x Now, setting the equations equal: 20 + 2x + 20 + 4x = 52 + 4x Or, x = 6 Sum of P3 and P4 = 20 + 4 × 6 = 44 P3, P4 = 19, 23 Answer: P4 = 23

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