Average of four consecutive prime numbers S1, S2, S3, and S4 is (16 + x). If the average of S1 and S2 is (12 + x) and the average of S3 and S4 is (12 + 3x), then find S4.
ATQ, Sum of S1, S2, S3, and S4 = (16 + x) × 4 = 64 + 4x Sum of S1 and S2 = (12 + x) × 2 = 24 + 2x Sum of S3 and S4 = (12 + 3x) × 2 = 24 + 6x Now, setting the equations equal: 24 + 2x + 24 + 6x = 64 + 4x Or, x = 4 Sum of S3 and S4 = 24 + 6 × 4 = 48 S3, S4 = 23, 29 Answer: S4 = 29
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