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ATQ, Let the two equal numbers be ‘c’ each Therefore, least number = (c – 70) 4th number = 4(c – 70) According to the question, 4(c – 70) + c – 70 + c + c = 4 × 200 Or, 8c – 280 = 800 Or, c = 1080/8 = 135 Therefore, 4 numbers are 135, 135, 65, and 260 Therefore, required average = (260 + 65)/2 = 162.5
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